What is the area of a trapezoid with bases of 6 cm and 10 cm, and a height of 4 cm?

What is the area of a trapezoid with bases of 6 cm and 10 cm, and a height of 4 cm?

• A. 24 cm²
• B. 28 cm²
• C. 32 cm²
• D. 40 cm²

Answer: (C)

To find the area of a trapezoid, you use the formula: Area = \( \frac{1}{2} \times (b_1 + b_2) \times h \) where \( b_1 \) and \( b_2 \) are the lengths of the two bases, and \( h \) is the height of the trapezoid. In this case, the bases are given as 6 cm and 10 cm, and the height is 4 cm. Plugging these values into the formula: 1. Calculate the sum of the bases: \( b_1 + b_2 = 6 \, \text{cm} + 10 \, \text{cm} = 16 \, \text{cm} \) 2. Multiply this sum by the height: \( 16 \, \text{cm} \times 4 \, \text{cm} = 64 \, \text{cm}^2 \) 3. Finally, take half of that product to find the area: \( \frac{1}{2} \times 64 \, \text{cm}^2 = 32 \, \text{cm

To find the area of a trapezoid, you use the formula:

Area = ( \frac{1}{2} \times (b_1 + b_2) \times h )

where ( b_1 ) and ( b_2 ) are the lengths of the two bases, and ( h ) is the height of the trapezoid.

In this case, the bases are given as 6 cm and 10 cm, and the height is 4 cm. Plugging these values into the formula:

1. Calculate the sum of the bases:

( b_1 + b_2 = 6 , \text{cm} + 10 , \text{cm} = 16 , \text{cm} )

2. Multiply this sum by the height:

( 16 , \text{cm} \times 4 , \text{cm} = 64 , \text{cm}^2 )

3. Finally, take half of that product to find the area:

( \frac{1}{2} \times 64 , \text{cm}^2 = 32 , \text{cm